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*To*: tesla-at-pupman-dot-com*Subject*: RE: More ISSTC theory stuff*From*: "Tesla list" <tesla-at-pupman-dot-com>*Date*: Mon, 07 Jun 2004 07:28:34 -0600*Resent-Date*: Mon, 7 Jun 2004 07:32:36 -0600*Resent-From*: tesla-at-pupman-dot-com*Resent-Message-ID*: <v4QGLD.A.4rD.y5GxAB-at-poodle>*Resent-Sender*: tesla-request-at-pupman-dot-com

Original poster: "Steve Conner" <steve.conner-at-optosci-dot-com> >This structure can be designed exactly to have any bandwidth, >and any voltage gain or any input resistance, by using the same >procedures used in the classical design of passive filters. OK... cool... I agree totally. But what I am trying to find out is the magic values of bandwidth, voltage gain, and input resistance, that will give biggest streamer output from a given set of IGBTs, with reasonable tolerance to detuning by streamer load. >It's also possible to make approximate designs by considering the >network as a series of two L-match impedance matching networks, >one C-L and the other L-C. I like this approach. I think that a lot of the design choices we _could_ make in the full bandpass filter network approach are constrained by other things. For instance the coupling will be limited due to clearances for primary-secondary flashover, and the voltage gain achievable in the primary will be limited (I imagine) by such things as flashovers between primary turns. With the L-match approach, the problem is reduced to matching the real part of the streamer load (several hundred kOhm) to the inverter output impedance (around 1 ohm) The inverter doesn't have an output impedance as such, but you can express the maximum current you want to draw as an impedance. (fundamental of inverter output voltage /(peak IGBT current you want/sqrt(2)) I say fundamental because the inverter output voltage is a square wave but our analysis will assume a sine wave. The current is a sine wave anyway. So my plan is to design the secondary according to good HV practice, choose the highest coupling I can without any risk of flashovers, then choose the primary L and C by treating it as an L-match. What do you think? Steve C.

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